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2x^2+2x=11.36
We move all terms to the left:
2x^2+2x-(11.36)=0
We add all the numbers together, and all the variables
2x^2+2x-11.36=0
a = 2; b = 2; c = -11.36;
Δ = b2-4ac
Δ = 22-4·2·(-11.36)
Δ = 94.88
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-\sqrt{94.88}}{2*2}=\frac{-2-\sqrt{94.88}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+\sqrt{94.88}}{2*2}=\frac{-2+\sqrt{94.88}}{4} $
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